Testing ..

x=a0+1a1+1a2+1a3+1a4 x = a_0 + \cfrac{1}{a_1 + \cfrac{1}{a_2 + \cfrac{1}{a_3 + \cfrac{1}{a_4} } } }

α,A,β,B,γ,Γ,π,Π,ϕ,φ,Φ\alpha, A, \beta, B, \gamma, \Gamma, \pi, \Pi, \phi, \varphi, \Phi

limxexp(x)=0\lim_{x \to \infty} \exp(-x) = 0

xa(modb)x \equiv a \pmod b

kn+1=n2+kn2kn1k_{n+1} = n^2 + k_n^2 - k_{n-1}

n!k!(nk)!=(nk)\frac{n!}{k!(n-k)!} = \binom{n}{k}

1x+1yyz\frac{\frac{1}{x}+\frac{1}{y}}{y-z}

[b]r(x1x2)×(x1x2)(y1y2y3y4) \frac{ \begin{array}{c}[b]{r} \left( x_1 x_2 \right)\\ \times \left( x'_1 x'_2 \right) \end{array} }{ \left( y_1y_2y_3y_4 \right) }

1+x+x2+x3+n\sqrt[n]{1+x+x^2+x^3+\ldots}

i=110ti\sum_{i=1}^{10} t_i

0exdx\int_0^\infty \mathrm{e}^{-x}\,\mathrm{d}x

abcdefghi \begin{matrix} a & b & c \\ d & e & f \\ g & h & i \end{matrix}

Am,n=(a1,1a1,2a1,na2,1a2,2a2,nam,1am,2am,n) A_{m,n} = \begin{pmatrix} a_{1,1} & a_{1,2} & \cdots & a_{1,n} \\ a_{2,1} & a_{2,2} & \cdots & a_{2,n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{m,1} & a_{m,2} & \cdots & a_{m,n} \end{pmatrix}

f(n)={n/2if $n$ is even(n+1)/2if $n$ is odd f(n) = \left\{ \begin{array}{l l} n/2 & \quad \text{if \$n\$ is even}\\ -(n+1)/2 & \quad \text{if \$n\$ is odd} \end{array} \right.

Note by JohnDonnie Celestre
5 years, 5 months ago

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Haha, good idea.

Finn Hulse - 5 years, 5 months ago

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