X went first. I'm making the assumption that
1. Both will complete your 3-in-a-line if they can (and hence win)
2. Both will play to prevent the other from getting a 3-in-the-line (and hence not lose immediately)
3. Other than that, you are allowed to play in any way.

If O went first, then by his second turn he must have obtained 2 in a row (since any 2 of the 3 O's are in a line). This means that X will need to block it (since X cannot win in the 2nd turn), thus the first 2 O's placed must be in the middle column (the order doesn't matter), and the 2nd X placed must be the top middle one. Hence, the third O placed must be in the bottom left corner, after which X will need to play in either the top right or bottom right to prevent the 3-in-a-line.

Hence, we are left with the case that X went first. We also need to verify that a sequence of moves is possible. See Aditya's comment.

It is "x's" turn.
I tried most of the moves that would lead to this and I could narrow down to one solution, where X first plays In the 1st row 2nd column, then zero is made in the centre. Next, x is made in the 2nd row 1st column and zer0 in the 3rd row 2nd column. Finally, x is played in the 1st box and the zero in the 3rd row 1st column. This might not be the perfect solution though.

If this is a classical tic-tac-toe,I think the moves that you have suggested in your solution is a bit illogical .They are not looking for a chance to get themselves in a row of 3 same symboles.

Then any two players playing rationally would never arrive at this situation. Though it is important to note that sometimes negligence can lead to this pattern. Methinks.

whoever went first - it's his turn
now we have to decide who went first
if we assume that x was not dumb 0 cannot possibly go first - i tried every possible move with 0 starting first and every time got to a situation where the THIRD move of x must be to block 0's next move which is obviously not the case here so we can safely assume that x went first and it's his turn

its X turn as it the player of X will not let the O player to get both ways to win without closing one path (diagonal or horizontal). Logically its X's turn

Well see,game starts with X,then O and again X and so on...
At any instant of the game Number of O CAN NEVER BE MORE THAN X,here number of X and O is same so it has to be X's turn

think about it like this x has one position from where he can win but but 0 has two winning positions.........so if 0 had to win he would have until now......but its not.....so naturally it is 0's turn....aye?

actually in both the players playing have made the blunder because 1 of the two players actually had a chance to win the game but refuse to do so. So, both x and o can the next turn

cross, my moves... 1st cross of second row, then zero of third row & second column, then cross of 1st row & 2nd column, then zero of middle one, then cross then zero ...so, next chance cross....too lazy to type reason

It has to be 'x' simply because any two of the three circles force the 'x' player to respond to it, assuming both players are playing 'reasonably' and not just filling up squares randomly - thus after the circle player's second move, 'x' must respond; after the circle player's third move, the X player must respond again; looking at the board, X has only responded once by blocking a line of three; its thus his turn again

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TopNewestX went first. I'm making the assumption that 1. Both will complete your 3-in-a-line if they can (and hence win) 2. Both will play to prevent the other from getting a 3-in-the-line (and hence not lose immediately) 3. Other than that, you are allowed to play in any way.

If O went first, then by his second turn he must have obtained 2 in a row (since any 2 of the 3 O's are in a line). This means that X will need to block it (since X cannot win in the 2nd turn), thus the first 2 O's placed must be in the middle column (the order doesn't matter), and the 2nd X placed must be the top middle one. Hence, the third O placed must be in the bottom left corner, after which X will need to play in either the top right or bottom right to prevent the 3-in-a-line.

Hence, we are left with the case that X went first. We also need to verify that a sequence of moves is possible. See Aditya's comment.

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It is "x's" turn. I tried most of the moves that would lead to this and I could narrow down to one solution, where X first plays In the 1st row 2nd column, then zero is made in the centre. Next, x is made in the 2nd row 1st column and zer0 in the 3rd row 2nd column. Finally, x is played in the 1st box and the zero in the 3rd row 1st column. This might not be the perfect solution though.

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If this is a classical tic-tac-toe,I think the moves that you have suggested in your solution is a bit illogical .They are not looking for a chance to get themselves in a row of 3 same symboles.

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Then any two players playing rationally would never arrive at this situation. Though it is important to note that sometimes negligence can lead to this pattern. Methinks.

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X

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it seems 0 has made a riddle 2 win the game becuz next is of X but unfortunately X may win hence next turn is of X

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next turn is of X bcuz he is not a fool to loose such an easy game

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arent we assuming that the players dont do a one move blunder??

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whoever went first - it's his turn now we have to decide who went first if we assume that x was not dumb 0 cannot possibly go first - i tried every possible move with 0 starting first and every time got to a situation where the THIRD move of x must be to block 0's next move which is obviously not the case here so we can safely assume that x went first and it's his turn

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its x's turn

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0 in that game fist user can be enered in a squre box first so enter 0 in next

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its X turn as it the player of X will not let the O player to get both ways to win without closing one path (diagonal or horizontal). Logically its X's turn

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Well talking about logic...X gave a chance to O for wining.. :)

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Well see,game starts with X,then O and again X and so on... At any instant of the game Number of O CAN NEVER BE MORE THAN X,here number of X and O is same so it has to be X's turn

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Dude, 'x' need not be first.

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yes..the game stars with X..

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of 0 one

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calvin sir can you help us with this?

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think about it like this x has one position from where he can win but but 0 has two winning positions.........so if 0 had to win he would have until now......but its not.....so naturally it is 0's turn....aye?

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X's turn. I tried to simulate it as if O had started but if that was the case O's moves would not be logical.

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the person who played first

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you have to either answer zero or cross. state your reason as well.

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i hv read a similar prob in a puzzle book...

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its turn of player using 0 symbol

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Case chase ! , I will scan and give you my solution today !

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actually in both the players playing have made the blunder because 1 of the two players actually had a chance to win the game but refuse to do so. So, both x and o can the next turn

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They refused to do so in the previous steps

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I agree. Got the same answer.

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I guess 0 because starting with the middle is usually the best first move in tic-tac-toe. Just based on common strategies used in this game.

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cross, my moves... 1st cross of second row, then zero of third row & second column, then cross of 1st row & 2nd column, then zero of middle one, then cross then zero ...so, next chance cross....too lazy to type reason

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It has to be 'x' simply because any two of the three circles force the 'x' player to respond to it, assuming both players are playing 'reasonably' and not just filling up squares randomly - thus after the circle player's second move, 'x' must respond; after the circle player's third move, the X player must respond again; looking at the board, X has only responded once by blocking a line of three; its thus his turn again

(Was wrong initially; edited)

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What if it is the opposite way round??

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x as usually x starts and they have 3 turns each

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