The AF Problem

                        If something over 0 is undefined, and if a part of an equation satisfies this condition, and if x=2 is just equal to 1/x=1/2 by cross-multiplying, then (x ^ { 3 } + y ^ { 3 } ) = 0 is equal to 1 / ( x ^ { 3 } + y ^ { 3 } ) = 1/0 by cross-multiplying giving and equation of 1 / ( x ^ { 3 } + y ^ { 3 } ) - 1/0 = 0; after doing least common denominator the result would be [ 0 - ( x ^ { 3 } + y ^ { 3 })] / 0 =0 which is - ( x ^ { 3 } + y ^ { 3 } ) /0 = 0, but it should not be equal to zero but undefined? Though if you solve it properly there are many solutions for this. Does it mean that all equations equal to 0 is undefined at the same time having a solution set? If not please explain why.

Note by Adrian Sing
3 years, 9 months ago

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  Easy Math Editor

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[example link](https://brilliant.org)example link
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    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

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# 4 spaces, and now they show
# up as a code block.

print "hello world"
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Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

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