# The distance

Imagine in the same arrangement , all spheres are of same radius $$2~cm$$ and kept on a horizontal plane, the distance between the top of the sphere kept above the three spheres from the plane is

Note by Tanishq Varshney
3 years, 1 month ago

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@Raghav Vaidyanathan , i got my answer as $$4+4\frac{\sqrt{6}}{3}$$

- 3 years, 1 month ago

A tetrahedron is formed of side $$4~cm$$. The height of tetrahedron from its base to the centre of sphere is $$4\frac{\sqrt{6}}{3}$$, and $$2~cm$$ below the base lies the plane, and $$2~cm$$ above the centre is the top, did i do correctly

- 3 years, 1 month ago

Looks like it's correct to me. I checked it right now.

- 3 years, 1 month ago

- 3 years, 1 month ago

The ans is 2$$\sqrt{\frac{8}{3}}$$

- 3 years, 1 month ago