I have come across a problem two days ago which I could not solve.It's a basic problem but i need a procedure for the problem.
A triangle of sides of lengths a,b,c and the angles opposite to the sides are A,B,C respectively , satisfies the following condition :
a + b = tan (C/2) [ atan (B) + btan (A) ]
The perimeter of the triangle is 36 cm...and the side length c = 16 cm...then the area of triangle is ____ .
[WHEN I ATTEMPTED A QUESTION IN I.M.O. ,THEY SAID IT IS ACTUALLY AN ISOSCELES TRIANGLE.......BUT I DON'T KNOW THE PROOF. ]