3816547290

A Special Number: the only one in which

```
Every digit is used,
Each digit is used only once, and
The first n digits are divisible by n, for n=1..10.
```

3 is divisible by 1,

38 is divisible by 2,

381 is divisible by 3,

3816 is divisible by 4,

38165 is divisible by 5,

381654 is divisible by 6,

3816547 is divisible by 7,

38165472 is divisible by 8,

381654729 is divisible by 9,

3816547290 is divisible by 10.

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestOn Brilliant there are question related to this number. This number can found out without hit-n-trial method.

Clearly the 5th and 10th digits are 5 & 0 respectively,

Now 4th digit can only be from 2 & 6 as 3rd digit is odd and for the number to be divisible by 4 its last two digits must be divisible by 4,

Sum of first 3, next 3 & next 3 digits must be divisible by 3,

Hence,

We get the following combinations for 4th,5th &6th digits - 258 or 654,

Now with use of divisibility of 8 we can figure out 6th,7th & 8th digits,

With help of less hard work we can figure out the number.

Log in to reply

I would like to clarify your solution-We know that a number is divisible by \(4\) when last two digits are divisible by \(4\) and there are no two digit numbers having \(4\) and \(8\) as last digits and are divisible by \(4\) therefore for \(4^{th}\) digit we can say that at the \(4^{th}\) place only \(2\) or \(4\) are possible digits.

Similarly , as \(8\) is divisible by \(4\) the \(8^{th}\) digit would be either \(2\) or \(4\). Then, as

\(Akshay\)told we can proceed to get the answer.Log in to reply

Hmmm... Well answered brother.. Thankss

Log in to reply

Good job, Falzan!

Log in to reply

i've always been intersred in relation between numbers .... awesome !!

Log in to reply

That's brilliant

Log in to reply

By the way I already knew that number.

Log in to reply

Wow, beautiful!

Log in to reply

Great Work.. Its Awesome// how did you found it?

Log in to reply