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The value of 0/0


we know one thing





now we take n=1,


0!=1 [Equation 1]

In the same way take n=0


(0-1)!=0!/0 [n!/n= n(n-1)(n-2)(n-3)...]

(-1)!=infinity [Equation 2] (1/0 assumes the value of infinity)

{We are getting the right answer as factorial of a negative number does not exist}

Now think how 0!=1

Now if we can write 2!=2*1

then we should try writing 0! in the same way.

so we write,

0!=0(-1)(-2)(-3)(-4)*....(till infinity)

0!=0*[(-1)!] {Take n=-1 in n(n-1)(n-2).....}


{Now we assume that infinity is a large number so zero multiplied by a large number is also zero)

we get 0!=0 [Equation 3]

Compare Equation 1 & 3

we get 1=0

which is WRONG

so we take infinity =n/0 [ where 'n' is any real number]

We get,

(infinity) *0 = (n/0) *0

=0/0 [Equation 4]

Now Compare Equation 1 & 4

we get 0/0=1.

Note by Vipul Maisske
2 years, 11 months ago

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Ty bro :) Vipul Maisske · 2 years, 9 months ago

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Bro nice try.. Ankit Upadhyay · 2 years, 9 months ago

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