Can \(y\) and \(x\) be real numbers? Does this system have solutions?
Chemical reaction S+E=SE=P+E

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TopNewestWoah. What were you trying to solve? – Ameya Daigavane · 10 months ago

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– Raffaele Piccirillo · 10 months ago

Modelling an enzimatic reaction :)Log in to reply

– Ameya Daigavane · 10 months ago

Using? A variation of Michelis-Menten?Log in to reply

– Raffaele Piccirillo · 10 months ago

Yes =) stating the rate of conversion x in different way :)Log in to reply

What about approximations? If you assume some concentrations/rate constants are much larger than others, then you can neglect many terms. But I'm sure you've thought about this already. – Ameya Daigavane · 10 months ago

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– Raffaele Piccirillo · 10 months ago

this is already the reducted model :) but the two therms can't be calculated so easy by my pc xDLog in to reply

If so, then there must be some real solution, right? (as we're modelling a real-world chemical reaction.) – Ameya Daigavane · 10 months ago

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– Raffaele Piccirillo · 10 months ago

0<y<1 and 0<x<0.1; y is a constant;x is the inverse of a time =)Log in to reply

– Ameya Daigavane · 10 months ago

Ah okay, now I'm seeing the problem. I can't really help you much more though - have you tried Mathematica Online?Log in to reply

– Raffaele Piccirillo · 10 months ago

Not yet,I don't know the website :)Log in to reply

here it is. There's a fifteen day free trial, which should be enough for your computations. – Ameya Daigavane · 10 months ago

Oh sure,Log in to reply

– Raffaele Piccirillo · 10 months ago

Thank you =)Log in to reply