Waste less time on Facebook — follow Brilliant.
×

There are real solutions?

Can \(y\) and \(x\) be real numbers? Does this system have solutions? Chemical reaction S+E=SE=P+E

Note by Raffaele Piccirillo
1 year, 7 months ago

No vote yet
1 vote

Comments

Sort by:

Top Newest

Woah. What were you trying to solve?

Ameya Daigavane - 1 year, 7 months ago

Log in to reply

Modelling an enzimatic reaction :)

Raffaele Piccirillo - 1 year, 7 months ago

Log in to reply

Using? A variation of Michelis-Menten?

Ameya Daigavane - 1 year, 7 months ago

Log in to reply

@Ameya Daigavane Yes =) stating the rate of conversion x in different way :)

Raffaele Piccirillo - 1 year, 7 months ago

Log in to reply

@Raffaele Piccirillo Haha woah cool! I knew it would be that :P
What about approximations? If you assume some concentrations/rate constants are much larger than others, then you can neglect many terms. But I'm sure you've thought about this already.

Ameya Daigavane - 1 year, 7 months ago

Log in to reply

@Ameya Daigavane this is already the reducted model :) but the two therms can't be calculated so easy by my pc xD

Raffaele Piccirillo - 1 year, 7 months ago

Log in to reply

@Raffaele Piccirillo Are x and y concentrations?
If so, then there must be some real solution, right? (as we're modelling a real-world chemical reaction.)

Ameya Daigavane - 1 year, 7 months ago

Log in to reply

@Ameya Daigavane 0<y<1 and 0<x<0.1; y is a constant;x is the inverse of a time =)

Raffaele Piccirillo - 1 year, 7 months ago

Log in to reply

@Raffaele Piccirillo Ah okay, now I'm seeing the problem. I can't really help you much more though - have you tried Mathematica Online?

Ameya Daigavane - 1 year, 7 months ago

Log in to reply

@Ameya Daigavane Not yet,I don't know the website :)

Raffaele Piccirillo - 1 year, 7 months ago

Log in to reply

@Raffaele Piccirillo Oh sure, here it is. There's a fifteen day free trial, which should be enough for your computations.

Ameya Daigavane - 1 year, 7 months ago

Log in to reply

@Ameya Daigavane Thank you =)

Raffaele Piccirillo - 1 year, 7 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...