Waste less time on Facebook — follow Brilliant.

Geometry Proof

Let the side length a regular hexagon be \(a\). Prove that the area of this regular hexagon is \(\dfrac{3\sqrt3 a^2}2 \).

Note by Rohit Camfar
1 month, 1 week ago

No vote yet
1 vote


Sort by:

Top Newest

divide hexagon to 6 - equilateral triangles each with side length (a) by joining the center of hexagon to each vetices.

area of each equilateral triangle = sqrt3/4*a^2

area of hexagon = 6sqrt3a^2 /4 = 3sqrt3a^2 /2 Ahmad Saad · 1 month, 1 week ago

Log in to reply


Problem Loading...

Note Loading...

Set Loading...