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Geometry Proof

Let the side length a regular hexagon be $$a$$. Prove that the area of this regular hexagon is $$\dfrac{3\sqrt3 a^2}2$$.

Note by Rohit Camfar
1 month, 1 week ago

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divide hexagon to 6 - equilateral triangles each with side length (a) by joining the center of hexagon to each vetices.

area of each equilateral triangle = sqrt3/4*a^2

area of hexagon = 6sqrt3a^2 /4 = 3sqrt3a^2 /2 · 1 month, 1 week ago