Well, assuming the room is cuboid in shape, the answer is option D. My reasoning is as follows:

The room has a total volume of \(18 parcels \times (1\times1\times 2) m^{3}/parcel = 36 m^{3}\)

You know the floor area is \(9m^{2}\) and so the height of the room is \(36m^{3} \div 9m^{2} = 4m\) This invalidates option B, since the height is already known.

Now, since you know that the internal dimensions are natural numbers, they can be \((3m \times 3m)\) or \((1m \times 9m)\).

Because you want to fit in cubes of side \(1m\), these dimensions do not matter, so long as they are natural numbers! The same number of cubes will fit in no matter what the dimensions are - hence, option A in invalidated.

Obviously, option C is useless - I don't care what you fit into the parcels, so long as they don't change its dimensions. And so, by elimination, option D is the right answer.

If you have less than or equal to 36 small parcels, you're good. If you've got more, they won't fit.

He packed 18 parcels of 2 cubic metres so now he know both height and floor area of the store now all that matters is how many small parcels are there so he can calculate whether they will fit or not

Now basically we have the info as follows :-
base area 9 sq. Mts
height 4m
hence total volume of container is 36 cubic mts
Now we have cubes of volume 1 cubic metre ....
we know that no. Of small parcels =
volumr of container ÷ vol. Of small parcel (the cube)
hence in order to have all the parcels to be exactly fit in the container we must know the number of parcels

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TopNewestWell, assuming the room is cuboid in shape, the answer is option D. My reasoning is as follows:

If you have less than or equal to 36 small parcels, you're good. If you've got more, they won't fit.

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He packed 18 parcels of 2 cubic metres so now he know both height and floor area of the store now all that matters is how many small parcels are there so he can calculate whether they will fit or not

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C, the highlighted option is the correct answer btw!

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Now basically we have the info as follows :- base area 9 sq. Mts height 4m hence total volume of container is 36 cubic mts Now we have cubes of volume 1 cubic metre .... we know that no. Of small parcels = volumr of container ÷ vol. Of small parcel (the cube) hence in order to have all the parcels to be exactly fit in the container we must know the number of parcels

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