Main post link -> https://brilliant.org/assessment/s/algebra-and-number-theory/1180156/

I find this week's 8th problem in Number theory and algebra (LEVEL 2) far more tough than the other problems of the set (mor than usual). What is your thought about this, is the problem too hard for level 2 or is it me that I'm afraid of complex numbers?

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TopNewestApply factorization and logic :) – Edward Elric · 3 years, 11 months ago

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let me give u a bit of a clue,the a part is a square number,and the b part is not a prime number – Beakal Tiliksew · 3 years, 11 months ago

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Josep ,just try to factorise the polynomial .It will give you an expression in x,y,z.The value of the expression can be easily found using the given information.

Please don't post questions when the set is live.– Vinay Shikhar · 3 years, 11 months agoLog in to reply

– Josep Burgaya Pujols · 3 years, 11 months ago

I didn't want the answer of the problem. I was just expressing my opinion that the problem is too hard for a Level 2 but if you say that it has a trick, then I was wrong ;)Log in to reply

Besides, you can always post comments after the problem set is closed. There's been a lot of discussion recently about "cheating" lately, and it is such a shame that there are students who seem to have missed the point of doing math problems, which is to learn mathematics and enjoy the beauty of problem solving. The reward is the feeling of solving a problem all by yourself, not some T-shirt or lanyard. – Hero P. · 3 years, 11 months ago

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– Josep Burgaya Pujols · 3 years, 11 months ago

I completely agree with you, we are here to learn math, not for some kind of prize.Log in to reply

Thanks for the response everyone, I'll have a look on te problem again in a few hours :) – Josep Burgaya Pujols · 3 years, 11 months ago

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look it deeply, you'll realize something I guess – Dullah Yagami · 3 years, 11 months ago

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I personally found the problem quite tricky. I suspect it's harder than the normal level 2, but you shouldn't be intimidated by the fact that x, y and z are complex, you (probably) know enough to do the problem, even if you don't have much experience with complex numbers. – Clifford Wilmot · 3 years, 11 months ago

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