@Rohit Gupta
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1 case)The drop would be perfectly spherical because sphere is the only shape with maximum volume but minimum surface area , so due to surface tension , it would be spherical.

2 case)I think its because when a perfectly spherical drop falls , it expiriences 'comparitively' low pressure at the front than at the end , so the end of the drop is squeezed while the front part is able to retain more spherical surface.
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Utkarsh Dwivedi
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2 years ago

@Rohit Gupta
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Okay, so o e more factor is that the tail of the rain drop is the water that was left behibd while falling but is still attached to rain drop. So, is my answer correct , sir?
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Utkarsh Dwivedi
·
2 years ago

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@Utkarsh Dwivedi
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I have already written the correct answer.. refer to my earlier comments with a diagram.
The diagram shows you how the shape of the rain drop should be in case it attains the terminal velocity..!!

And in case when we neglect the air resistance then it should be spherical..!!
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Rohit Gupta
·
2 years ago

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@Rohit Gupta
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Sir, will the drop have larger curvature toward the ground in the presence of air drag?
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Mayank Chaturvedi
·
2 years ago

Now think why drop is spherical in (i) case??
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Rohit Gupta
·
2 years ago

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@Rohit Gupta
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I am extremely sorry for making you post same answer twice.......Can you please explain what is \({ P }_{ A },{ P }_{ B }\quad and\quad { P }_{ C }\) and also the relation used in the solution.
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Mayank Chaturvedi
·
2 years ago

## Comments

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TopNewestNow think why drop is spherical in (i) case?? – Rohit Gupta · 2 years ago

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Teardrop.

Edit: the answer to part 2 may not be a teardrop shape. Check wikipedia. – Raghav Vaidyanathan · 2 years ago

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– Rohit Gupta · 2 years ago

In second case drop will have more radius of curvature at the bottom or at the top??Log in to reply

– Raghav Vaidyanathan · 2 years ago

The radius of curvature will be more at the bottom, but it will not be a teardrop.Log in to reply

– Parth Tandon · 2 years ago

more at the bottom, i thinkLog in to reply

– Rohit Gupta · 2 years ago

Can you justify?? your answer..??Log in to reply

– Kalash Verma · 2 years ago

BECAUSE then it will be perfectly aerodynamic in shape ans will have least DragLog in to reply

@Kalash Verma What is your answer for the shape of the drop in the two cases?? – Rohit Gupta · 2 years ago

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– Kalash Verma · 2 years ago

Same as Raghav Vaidyanathan. The second one will be in a shape like 💦Curved at the top pointed in the end.Log in to reply

The answer in second case should be reverse... The top surface should be of more radius of curvature than the bottom one.. – Rohit Gupta · 2 years ago

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– Kalash Verma · 2 years ago

Yeah You are right.I just read about it.I got mistake in my thinkingLog in to reply

– Rohit Gupta · 2 years ago

:)Log in to reply

2 case)I think its because when a perfectly spherical drop falls , it expiriences 'comparitively' low pressure at the front than at the end , so the end of the drop is squeezed while the front part is able to retain more spherical surface. – Utkarsh Dwivedi · 2 years ago

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– Rohit Gupta · 2 years ago

Factor of gravity is also needed to be taken in the explanation..!!Log in to reply

– Utkarsh Dwivedi · 2 years ago

Okay, so o e more factor is that the tail of the rain drop is the water that was left behibd while falling but is still attached to rain drop. So, is my answer correct , sir?Log in to reply

And in case when we neglect the air resistance then it should be spherical..!! – Rohit Gupta · 2 years ago

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– Mayank Chaturvedi · 2 years ago

Sir, will the drop have larger curvature toward the ground in the presence of air drag?Log in to reply

I am posting the solution again...!!

Now think why drop is spherical in (i) case?? – Rohit Gupta · 2 years ago

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– Mayank Chaturvedi · 2 years ago

I am extremely sorry for making you post same answer twice.......Can you please explain what is \({ P }_{ A },{ P }_{ B }\quad and\quad { P }_{ C }\) and also the relation used in the solution.Log in to reply