Solve \(\displaystyle{\frac{\tan(x) - \sin(x)}{\tan(x)+ \sin(x)} = \frac{\sec(x)-1}{\sec(x)+1}}\) for all values of \(x\) if \(x\) is measure in radians.

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TopNewestJust divide numerator and denominator by sin(x) and you get the result! – Brilliant Member · 1 year, 6 months ago

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Yes agree with Svatejas Shivakumar .. – Ravi Hammad · 1 year, 5 months ago

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