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Trigonometric problem 3

Prove that \([ \cos^{-1} \circ \cos ] (x) = [\cos \circ \cos^{-1}] (x) \) find the value of \(x\).

Note by Cedie Camomot
1 year, 9 months ago

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\(cos(cos^{-1}x)= x\) for \(x\in[-1,1]\)

& \(cos^{-1}(cosx)=x\) for \(x\in[0,\pi]\)

So \(cos(cos^{-1}x)=cos^{-1}(cosx)\) only \(x\in[0,1]\)

Yash Dev Lamba - 1 year, 9 months ago

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