The Image shows all the Details.., The correct option is B.., I want to know B is the answer

The Image shows all the Details.., The correct option is B.., I want to know B is the answer

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestNotice that \[ \begin{align*} n = \sec \theta + \csc \theta &= \frac{1}{\cos \theta} + \frac{1}{\sin \theta} \\ &= \frac{\sin \theta + \cos \theta}{\sin \theta \cos \theta} \\ &= \frac{m}{\sin \theta \cos \theta}. \end{align*} \] Also, if we square the first given equation, we find that \[ m^2 = \sin^2 \theta + \cos^2 \theta + 2 \sin \theta \cos \theta \\ m^2 - 1 = 2 \sin \theta \cos \theta \\ \frac{m^2 - 1}{2} = \sin \theta \cos \theta. \] Therefore, \[ n = \frac{2m}{m^2 - 1} \\ 2m = n(m^2 - 1) \] and the answer is B. – Josh Petrin · 3 years, 8 months ago

Log in to reply

B – Melad Jalali · 3 years, 8 months ago

Log in to reply