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PROVE THAT SIN^4THETA- COS^4THETA=2SIN(SQ)THETA-1

Note by Rishit Joshi 4 years, 6 months ago

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We have-

\(LHS = Sin^4\theta - Cos^4\theta\)

\(= (Sin^2\theta + Cos^2\theta)(Sin^2\theta - Cos^2\theta)\)

\(= Sin^2\theta - Cos^2\theta\)

\(= Sin^2\theta - (1 - Sin^2\theta)\)

\(= 2Sin^2\theta - 1 = RHS.\)

Hence Proved.

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Yeah @Akshat ! Correct !

thanx bro

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Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

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TopNewestWe have-

\(LHS = Sin^4\theta - Cos^4\theta\)

\(= (Sin^2\theta + Cos^2\theta)(Sin^2\theta - Cos^2\theta)\)

\(= Sin^2\theta - Cos^2\theta\)

\(= Sin^2\theta - (1 - Sin^2\theta)\)

\(= 2Sin^2\theta - 1 = RHS.\)

Hence Proved.Log in to reply

Yeah @Akshat ! Correct !

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thanx bro

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