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# trigonometry ratio and their relation

PROVE THAT SIN^4THETA- COS^4THETA=2SIN(SQ)THETA-1

Note by Rishit Joshi
4 years, 6 months ago

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We have-

$$LHS = Sin^4\theta - Cos^4\theta$$

$$= (Sin^2\theta + Cos^2\theta)(Sin^2\theta - Cos^2\theta)$$

$$= Sin^2\theta - Cos^2\theta$$

$$= Sin^2\theta - (1 - Sin^2\theta)$$

$$= 2Sin^2\theta - 1 = RHS.$$

Hence Proved.

- 4 years, 6 months ago

Yeah @Akshat ! Correct !

- 4 years, 6 months ago

thanx bro

- 4 years, 6 months ago