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# try this ....

the largest angle of a triangle is equal to the sum of other two triangles. the smallest angle is 1/4 of the largest angle .find the angles of the triangle.

Note by Pooja Arora
3 years, 4 months ago

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Let largest angle be $$4x$$

then smallest angle = 1/4 of largest angle = $$x$$

Therefore, middle (or third) angle should be --> $$180 - (4x +x) = 180 - 5x$$

But the first statement says that sum of two angles = largest angle

=> $$x + (180 - 5x) = 4x$$

=> $$x = 22.5 ^ \circ$$

So the angles are --> $$90 ^ \circ , 67.5 ^ \circ , 22.5 ^ \circ$$

thanx a lot... · 3 years, 4 months ago

The first statement gives us that the largest angle is of $$90^{\circ}$$ The second statement gives us the smallest angle to be $$22.5^{\circ}$$. So the angles are $$90^{\circ}$$, $$22.5^{\circ}$$ , $$67.5^{\circ}$$ · 3 years, 4 months ago

thanku so much.. · 3 years, 4 months ago

Let the largest angle be $$4x$$

Then, it says that the smallest angle is $$\frac {1}{4}$$ of the largest angle which would be $$x$$

So, the last angle would be $$4x-x=3x$$

Lets make it as $$4x+3x+x=180\Rightarrow8x=180$$ So, $$x=22.5$$, $$3x=67.5$$, and $$4x=90$$ · 3 years, 4 months ago