the largest angle of a triangle is equal to the sum of other two triangles. the smallest angle is 1/4 of the largest angle .find the angles of the triangle.

No vote yet

2 votes

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestLet largest angle be \(4x\)

then smallest angle = 1/4 of largest angle = \(x\)

Therefore, middle (or third) angle should be --> \(180 - (4x +x) = 180 - 5x\)

But the first statement says that sum of two angles = largest angle

=> \(x + (180 - 5x) = 4x\)

=> \(x = 22.5 ^ \circ\)

So the angles are --> \(90 ^ \circ , 67.5 ^ \circ , 22.5 ^ \circ\)

Click Here – Kishlaya Jaiswal · 4 years, 1 month ago

Log in to reply

– Pooja Arora · 4 years, 1 month ago

thanx a lot...Log in to reply

The first statement gives us that the largest angle is of \( 90^{\circ}\) The second statement gives us the smallest angle to be \(22.5^{\circ}\). So the angles are \( 90^{\circ}\), \(22.5^{\circ}\) , \(67.5^{\circ}\) – Vikram Waradpande · 4 years, 1 month ago

Log in to reply

– Pooja Arora · 4 years, 1 month ago

thanku so much..Log in to reply

Let the largest angle be \(4x\)

Then, it says that the smallest angle is \(\frac {1}{4}\) of the largest angle which would be \(x\)

So, the last angle would be \(4x-x=3x\)

Lets make it as \(4x+3x+x=180\Rightarrow8x=180\) So, \(x=22.5\), \(3x=67.5\), and \(4x=90\) – Timothy Wong · 4 years, 1 month ago

Log in to reply