Waste less time on Facebook — follow Brilliant.

Vieta jumping

I've not come across Vieta jumping before, but apparently it can be used to solve in proving this:

\(\displaystyle 2+2\sqrt{12n^2+1} \in \mathbb{N} \Leftrightarrow \sqrt{2+2\sqrt{12n^2+1}} \in \mathbb{N}, n \in \mathbb{N}.\)

How? Is there a general form of problem that Vieta jumping is useful for? I've read the wikipedia page, but I don't find its explanation useful.

Note by A L
3 years, 3 months ago

No vote yet
2 votes


Sort by:

Top Newest

I dont think this would require veita jumping from anywhere :3 Sagnik Saha · 2 years, 7 months ago

Log in to reply


Problem Loading...

Note Loading...

Set Loading...