# Wanna Share Some Math Tricks?

Hi fellow Brilliantians out there! As any kid studying for a competitive exam, an arsenal of vast number of tricks, which make calculations simple, is a must. Why not try & write some of these here in this feed?

Here are some of mine -

### Multiplying a number by 11?

Do it this way!

$11 \times 23 = 2 (2+3) 3 = 253$

Hey presto! You got the right answer!

Take another one- $11 \times 49 = 4 (4+9) 9 = 4 (13) 9 = (4+1) 3 9 = 539$

Just Brilliant! (Pun intended).

### Squaring a number ending with 5

Take the case of $$145^2$$.

1. Take the number other than 5 & consider it as a whole (in this case 14).

2. Multiply it by its consecutive integer (here $$14 \times 15 = 210$$).

3. Join 25 at the back of the number you just got (here 21025).

And that, my dear friend, is the answer! (Check if you don't believe me!).

Remember: This is only valid for the squares of integers ending with 5.

Note by Ameya Salankar
3 years, 8 months ago

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@Ameya Salankar I know the fastest trick to find the cube root of any number.(But you should know that the number is a cube.)

Eg- Find the cube root of 474552

Units digit is 2. This means that the units place of the cube root will be 8. ($$8^3 = 512.$$)

Now, cancel the last 3 digits of the number. Hence, we are left with 474.(You have to always cancel the last 3 digits)

Now, you have to find the cube which is smaller than 474 but closest to 474. It is 343. 343 is $$7^3$$.

Therefore, our required answer is $$\boxed{78}$$.

- 3 years, 8 months ago

You forgot the 8 after the 7. It should be 78. Nice one though!

- 3 years, 8 months ago

Oh! Thanks

- 3 years, 8 months ago

Oh! I knew this one! I kinda forgot... (I am known for my forgetfulness!)

- 3 years, 8 months ago

just came across this image .Hope you may like it

abc

- 3 years, 8 months ago

déjà vu (its real this time!). By the way, which book is that? (The trick on the next page....?)

- 3 years, 8 months ago

I have actually taken it from my gmail account.somebody had posted it

- 3 years, 8 months ago

Wow! This is a nice trick.

- 3 years, 8 months ago

So how does this work?

- 3 years, 8 months ago

@Ameya Salankar Thanks for tagging me.

Now that you have given a way to square numbers ending with a $$5$$, here is a general way to square numbers ending with any digit.

$${ a }^{ 2 }-{ b }^{ 2 }=(a+b)(a-b)$$

$${ a }^{ 2 }=(a+b)(a-b)+{ b }^{2}$$

So for example if you wanted to calculate the square of $$23$$, then

$${ 23 }^{ 2 }=(23+3)(23-3)+{ 3 }^{ 2 }=20\times 26+9=\boxed{529}$$.

I prefer this method because doing ($$26\times 20$$) is easier than doing ($$23\times 23$$)

The method provided by Ameya to square numbers ending in $$5$$ is also based on the above identity.

$${ 145 }^{ 2 }=(145+5)(145-5)+{ 5 }^{ 2 }=140\times 150+25=21000+25=\boxed{21025}$$

Hope this helped :)

- 3 years, 8 months ago

A treasure box of math tricks

Just browsing Arvind gupta toys.com site , a very good site containing interesting and valuable information on all topics. Just click this link

- 3 years, 8 months ago

This is not exactly ground-breaking, but it helps me.

To find $$a^2$$, given $$(a-1)^2$$, just add $$(a-1) and (a)$$ to get the desired result. This can be repeated many times to get $$a^2$$ from $$(a-n)^2$$

- 3 years, 8 months ago

Another way to find square of any two digit number:- Consider a two digit number AB so we can write it as:- AB=10A+B now squaring both sides:- $(AB)^2=100A^2+10AB+B^2$ Now this equation can be used to find square of any two digit number eg:- To find square of 16:-

1)find the square of last digit and write one's digit of answer obtained and take ten's digit as carry for next step(in this case square of 6 is 36 so write 6 in your answer and take 3 as carry)

2)multiply both digits of number with each other and 2 and add the carry obtained in previous step(in this case 1×6×2+3) Now write one's digit of number obtained in second step to left of number obtained in first step and take ten's digit of number obtained in second step as carry(in this case i obtained 6 from first step and 5 from second step so write ....56 also i got 1as carry from second step)

3)now find square of ten's digit and add the carry obtained in second step to it and write result obtained with your answer(in this case $$1^2+1=2$$ and write it to left of your answer (256) ) I hope my wordings make sense

- 3 years, 8 months ago

Let me tag some of you here
@Krishna Ar,Sharky Kesa, Finn Hulse , Anik Mandal, milind prabhu , Calvin Lin , Avineil Jain , Aditya Raut , Satvik Golechha Agnishom Chattopadhyay ,Daniel Liu , Nanayaranaraknas Vahdam @Dinesh Chavan @Sreejato Bhattacharya

Oh no! This list is getting too long!

- 3 years, 8 months ago

That is nice. Why don't you create a wiki page called Vedic Math? Many people could put together their knowledge since wiki pages are collaborative.

Staff - 3 years, 8 months ago

Yeah. That's right. You must consider it Ameya...(Back after a long break?..How was Kvpy?) and you too agnishom ...how was it?

- 3 years, 8 months ago

@Krishna Ar Forget KVPY. I couldn't believe that was Ameya Salankar giving KVPY like that!

Fell face down! I am going to try harder next year.

- 3 years, 8 months ago

How many marks expected???? Please tell

- 3 years, 8 months ago

@GAUTAM SHARMA, my marks are out of hell! You first....

- 3 years, 8 months ago

hahahaha i think its better to leave it here as the result will speak after a month.

- 3 years, 8 months ago

I dont think it was tough to cross last year's cutoff (I mean 53)

- 3 years, 8 months ago

at that time we look like ""ISHAN AWASTHI OF TAARE ZAMEEN PAR"""

- 3 years, 8 months ago

LOL!

- 3 years, 8 months ago

EEEEAAAArgh! Avast ye! I ain't even getting 45! Thou shalt not rub salt on my wounds!

(Just Joking but the marks are real)

- 3 years, 8 months ago

:O (Shocked and gaping) Bio gave you free 25 marks right? :P (Sorry for the cocky manner in which I reply :P )

- 3 years, 8 months ago

@Krishna Ar Yes. And I want the same treatment (shocked & gaping) when I bring near perfect marks next year....(just being realistic!)

- 3 years, 8 months ago

:D :D :D Best of luck

- 3 years, 8 months ago

Me too less than 45.So we are in the same boat!!!!!!!!!!!!!!

- 3 years, 8 months ago

yeah last year was easy as organic chem was less but this year it came out of nowhere and also weightage of electrostatics and geometrical optics was less.

- 3 years, 8 months ago

I dont really focus on these now! Math +Bio give you home easy 45+ marks...leave the physics and chem parts... (Sorry If i sound a bit cocky)

- 3 years, 8 months ago

I too messed up kvpy.

- 3 years, 8 months ago

Dont worry! You'll do much better and that's the spirit.

- 3 years, 8 months ago

- 3 years, 8 months ago

It went the same way as your KVPY :P

- 3 years, 8 months ago

it must have gone good .

- 3 years, 8 months ago

KVPY didn't go to well

Staff - 3 years, 8 months ago

To square any number ending with the number six. For example 3636 Step 1: Attach 2 to the number before six . (The number here is 3, so attaching 2 to 3, we get 32) Step 2: Multiply the result by 1+the number before six (here it corresponds to 1+3=4. so result times this = 324 =128) Step 3 : Add 1 to this new result (we get 128+1=129) Step 4: attach 6 to the answer. (we get 1296)

therefore, 36*36=1296. I know its very complicated. It might be be useful for smaller numbers though

- 3 years, 8 months ago

Everytime what I'm doing is making words into numbers and finding their $$\pmod{11}$$ value ! Almost all words I come across, I think of them as numbers and then try some arrangements in them like giving space so that it becomes divisible by 11 :P Sounds insane but that's my most favorite timepass :P

And my love about "11" is also the reason why this set was made ^_^

About tricks, I've got an awesome file, which has many many many tricks like the ones in your note... I hope you'll like them ... (On google, shared with all who have the link, here's the link - Maths PDF )

- 3 years, 8 months ago

If you want to find out square root of a number (approx.) then use this vedic math method:

sqrt(any number)=sqrt(nearest square) - {(nearest square)-(original number)}/[2 x sqrt(nearest square)]

For example: we want sqrt(22) then find nearest square of it that is 25. Now, sqrt(22)=5-(25-22)/(2 x 5)=5-3/10=4.7 Actual value of sqrt(22) is 4.69

NOTE:sqrt(a) means square root of 'a'

- 3 years, 8 months ago

Actually I didn't quite understand this trick. Could you please use $$\LaTeX$$? @Vaibhav Jain

- 3 years, 8 months ago

Given something symmetrical you have to multiply or add, pair opposite up.

Example: Evaluate $$\sqrt{12\cdot 13\cdot 14\cdot 15+1}+\sqrt{16\cdot 17\cdot 18\cdot 19+1}$$

Pair up opposites and multiply: $$\sqrt{(12\cdot 15)\cdot (13\cdot 14)+1}+\sqrt{(16\cdot 19)\cdot (17\cdot 18)+1}$$

Difference of squares: $$\sqrt{(180+1)^2-1^2+1}+\sqrt{(304+1)^2-1^2+1}$$

Simplify: $$(180+1)+(304+1)=\boxed{486}$$

- 3 years, 8 months ago

Hey I am having PSA on this 20th please give me some tips or tricks to help me!

- 3 years, 8 months ago

For PSA (assuming you are in 9th) there is no need for special tricks but i have some tips for you- 1. Carefully read all paragraphs related to questions because most answers are in them specially in science and formulae are specified in text or you can derive them easily in maths.

2.There is no specified section for social studies but there is a section related to moral science and marks for S.St are calculated from this section. 3.English is quite simple and most of the reference can be taken from paragraphs. 4. No need to hurry because their is plenty of time .

BEST OF LUCK> thats all.

- 3 years, 8 months ago

A way to find that a number(not very large) is prime or not is that take square root of that number and check its divisibility by prime no. less then square root, if it is not divisible by primes less than square root the given no. is prime.

- 3 years, 8 months ago

If anybody wants to learn some divisibility rules he can do it here

- 3 years, 8 months ago

An easy method for finding the digital root of any number is to cast out $$9's$$ and the group's of digits which add up to nine.This is done by crossing out any nines in the number or any two digits adding up to $$9$$.The numbers which are left at the end give the digital root of the number.If there is nothing left after casting out the nines,then the digital root is$$9$$.

- 3 years, 8 months ago

Wow. Awesome I am trying it

- 3 years, 8 months ago

the sum of positive odd numbers is given by n>2 ; 1 +3 =4 ;22 1+3 +5 =33 1+3 +5 +7 +9 =25 ; 5*5 just count odd numbers. square it.you will get sum of odd numbers.

- 3 years, 8 months ago

Well I have another method to find the product when a number is multiplied by 11.Here it goes:

Suppose you have to multiply $$13,423$$by $$11$$

Step 1:Write down the number with a nought placed on both ends.

Step 2:Add the final two digits to get the units digits of the product.

Step3:For the tens digit,add the final two digits at that point and continue in this fashion to get the product.

For example,$$013,4230$$-Units digit $$0+3=3$$

Tens digit=\\$$3\+2=5\\$$

Hundreds digit =\\$$2\+4=6\\$$

Continue this way to get the product as $$147,653$$

- 3 years, 8 months ago

lets see....To find the square of any number ending with 5. like 25x25=(2x3)25 i.e.625 65x65=(6x7)25i.e.4225 so, basically n5xn5=(n x (n+1))25 Try it out

- 3 years, 8 months ago

State and prove thales theorem?

- 3 years, 8 months ago