Want to know the method

Q1) In how many ways a triangle can be formed by choosing numbers from the set {1,2,3...,10}\{1,2,3...,10\} .

Q2) I dont know the question exactly, But it says six ants are on the edge of a regular octahedron such that no two are on the same edge.They start moving on the adjacent edges, find the probability that no two ants arrive on the same vertex.

Q3) the figure is above, in how many ways can AA reach BB?

Q4) Number of integral pairs (x,y)(x,y) satisfying a+ib=(a+ib)2002a+ib=(a+ib)^{2002} where i=1i=\sqrt{-1}

Note by Tanishq Varshney
4 years, 5 months ago

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Q3. This is a binary situation, either up or down path hence total ways are 2n1.\displaystyle {2} ^ {n - 1}.

Rajen Kapur - 4 years, 5 months ago

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Sir, Do you mind explaining? I can't understand the formula : 2n12^{n-1}

Vishwak Srinivasan - 4 years, 5 months ago

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To reach B , the nth line must be compulsorily taken and hence the nth line has only one choice. But in the first (n-1) lines one can take the upper path or the lower path, hence each of these (n-1) lines has 2 possibilities. Thus by product rule , total ways =2n1×1=2n1= 2^{n-1} \times 1 = 2^{n-1} ways. Try a similar problem here.

Nihar Mahajan - 4 years, 5 months ago

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sorry guys i don't have their answers

Tanishq Varshney - 4 years, 5 months ago

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Dude, the triangles question. I think you can only do it by counting.

Take three cases: equilateral, isoceles and scalene.

Equilateral is simple.

Isoceles : Let the sides be aa and bb and let aa be the side which is equal. Then probably use Triangle Inequality.

Scalene Take two cases right triangles and normal triangles. Again triangle inequality must do the trick.

My method is very long. There must be a shorter way. Hope there is.

Vishwak Srinivasan - 4 years, 5 months ago

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Try playing with small cases for motivation and ease. Then see if you can arrive at a general idea. I say, start with a set A={1,2,3,4}A = \{1,2,3,4\} .

Vishwak Srinivasan - 4 years, 5 months ago

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Q4) It is easy to see that a+ib=1or0|a+ib|=1 or 0. Therefore, the answer will consist of all the 2001th2001^{th} roots of unity, as well as 0+0i0+0i.

Raghav Vaidyanathan - 4 years, 5 months ago

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These All are questions from IPU CET 2015 which was held on 17th May,2015 @Tanishq Varshney , I too want to know the answers .For Q2 i think there's already a probem (similar) on b'ant, i just don't recall it correctly

Kunal Gupta - 4 years, 5 months ago

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add me up on whatsapp with +2348029770297

Ayanlaja Adebola - 4 years, 5 months ago

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Who in the blue hell, r u jabroni , and i feel that no one is lunatic enough to add u or contact u 😝 becoz u r a complete stranger to me

Kyle Finch - 4 years, 5 months ago

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