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Is there any way to find the product, \(1^1 \times 2^2 \times \cdots \times n^n\)?

Note by Shithil Islam
7 months, 1 week ago

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There is no shortcut to find this product , however you can change the product a little bit.

\[ \displaystyle\prod_{r=1}^{n} r^r = \displaystyle\prod_{r=1}^{n} r! \dbinom{n}{r} \] Sambhrant Sachan · 7 months, 1 week ago

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