What are the chances?

If you choose the answer to this question at random, what is the probability that it will be correct?

a) $25$ %

b) $50$ %

c) $0$ %

d) $25$ %

Good Luck. :)

#Combinatorics #Probability #JustForFun #MathJoke

$</code> ... <code>$ $< / c o d e > . . . < c o d e >$ ."> Easy Math Editor

Markdown	Appears as
`italics` or `_italics_`	italics
`bold` or `__bold__`	bold
- bulleted - list	bulleted list
1. numbered 2. list	numbered list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1 paragraph 2	paragraph 1 paragraph 2
`[example link](https://brilliant.org)`	example link
`> This is a quote`	This is a quote
# I indented these lines # 4 spaces, and now they show # up as a code block. print "hello world"	# I indented these lines # 4 spaces, and now they show # up as a code block. print "hello world"

Math	Appears as
Remember to wrap math in $</span> ... <span>$ or $</span> ... <span>$ to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

Sort by:

Top Newest

25%

Ashish Sharma - 5 years, 1 month ago

Why 25% ?

Muzaffar Ahmed - 5 years, 1 month ago

50%

Anudeep Saketh - 5 years, 1 month ago

Why 50% ?

Muzaffar Ahmed - 5 years, 1 month ago

25 % . Because there are four options each contributing 25 %

santosh kumar - 5 years, 1 month ago

Not so simple, man, not so simple

Muzaffar Ahmed - 5 years, 1 month ago

pray tell us the answer!!!!!!!!!

Mayank Holmes - 5 years, 1 month ago

@Mayank Holmes – I guess these sort of questions are good for discussions rather for finding answers. For any answer there is a contradictory statement ......:) how about considering both 25% into single unit and the remaining 0 and 50 we get one more combination 1/3*100

santosh kumar - 5 years, 1 month ago

@Santosh Kumar – They are not one unit.. They are different options and the question is about choosing one option randomly...

Muzaffar Ahmed - 5 years, 1 month ago

25%

Karthik Akondi - 4 years, 9 months ago

0% is the correct answer .............. if it would have been 25% then if we chose randomly, there are 2 choices out of a total of four , that seem optimal ( i.e. option(a and (d ) so that would mean that the probability would be equal to 50 % ........ Contradictory! if it would have been 50% , then it would have meant that only one choice out of the four is correct i.e. 25%... this answer is also contradictory to itself.......... if it would have been 0% then again it would imply that one choice out of the four is correct i.e. 25% ...... hence it seems that none of the option is correct ......... that leads us to the answer 0% , and hence this answer is not in contrary to itself!!!!!!!

Mayank Holmes - 5 years, 1 month ago

If 0% is correct, then it is one of the four options, which would give you 25% probability again.

Muzaffar Ahmed - 5 years, 1 month ago

Agree. Can't be zero percent.If one of the options is correct and the user selects it randomly it definitely will have a probability. I will still stick to 25% . because among 4 options only one is correct and the probability for that becomes 25%(1/4 multiloed by 100)

santosh kumar - 5 years, 1 month ago

@Santosh Kumar – There are 2 instances of the option 25%, so if 25% is correct, you will have $\frac{2}{4} \times 100 = 50$ % probability.

Muzaffar Ahmed - 5 years, 1 month ago

@Muzaffar Ahmed – Oop missed it didn't notice 25 repeating again

santosh kumar - 5 years, 1 month ago

50%

rishabh singhal - 5 years, 1 month ago