@Mayank Holmes
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I guess these sort of questions are good for discussions rather for finding answers.
For any answer there is a contradictory statement ......:) how about considering both 25% into single unit and the remaining 0 and 50 we get one more combination 1/3*100

0% is the correct answer ..............
if it would have been 25% then if we chose randomly, there are 2 choices out of a total of four , that seem optimal ( i.e. option(a and (d ) so that would mean that the probability would be equal to 50 % ........ Contradictory!
if it would have been 50% , then it would have meant that only one choice out of the four is correct i.e. 25%... this answer is also contradictory to itself..........
if it would have been 0% then again it would imply that one choice out of the four is correct i.e. 25% ...... hence it seems that none of the option is correct ......... that leads us to the answer 0% , and hence this answer is not in contrary to itself!!!!!!!

Agree. Can't be zero percent.If one of the options is correct and the user selects it randomly it definitely will have a probability. I will still stick to 25% . because among 4 options only one is correct and the probability for that becomes 25%(1/4 multiloed by 100)

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## Comments

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Why 25% ?

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50%

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Why 50% ?

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25 % . Because there are four options each contributing 25 %

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Not so simple, man, not so simple

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pray tell us the answer!!!!!!!!!

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25%

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0% is the correct answer .............. if it would have been 25% then if we chose randomly, there are 2 choices out of a total of four , that seem optimal ( i.e. option(a and (d ) so that would mean that the probability would be equal to 50 % ........ Contradictory! if it would have been 50% , then it would have meant that only one choice out of the four is correct i.e. 25%... this answer is also contradictory to itself.......... if it would have been 0% then again it would imply that one choice out of the four is correct i.e. 25% ...... hence it seems that none of the option is correct ......... that leads us to the answer 0% , and hence this answer is not in contrary to itself!!!!!!!

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If 0% is correct, then it is one of the four options, which would give you 25% probability again.

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Agree. Can't be zero percent.If one of the options is correct and the user selects it randomly it definitely will have a probability. I will still stick to 25% . because among 4 options only one is correct and the probability for that becomes 25%(1/4 multiloed by 100)

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$\frac{2}{4} \times 100 = 50$ % probability.

There are 2 instances of the option 25%, so if 25% is correct, you will haveLog in to reply

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50%

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