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# What are

What are the bonds present in $$\ce{NaOH}$$?

Note by Shashidhar 123
1 year, 4 months ago

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## Comments

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The bond between $$Na$$ and $$O$$ will be ionic in nature due to the greater electronegativity difference between the two and also due to the low Ionization Enthalpy of $$Na$$ and high electron affinity of $$O$$. The bond between $$O$$ and $$H$$ will be a polar covalent bond according to the Fajan's Rule as the size of $$H$$ is very small and the electrons are pulled more towards $$O$$ as it has greater electronegativity.

When $$NaOH$$ is dissolved in $$H_2 O$$ it dissociates into $$Na^+$$ and $$OH^-$$ ions, thus showing that ionic bond breaks in a polar solvent like $$H_2 O$$ while covalent bond does not.

- 1 year, 3 months ago

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