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What is the charge on the capacotor?

Please help me with the problem in the image.(ignore the part written other than in english)

Q:Consider the situation shown in the figure. The capacitor A has a charge q on it whereas B is uncharged.The charge appearing on the capacitor B a long time after the switch is closed is:

Note by Rajath Krishna R
4 years, 4 months ago

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Ans. should be either \((1)zero\) or \((2)\frac{q}{2}\)

The negative charge \(q\) on the right capacitor plate of A is equally distributed between itself and the left plate of capacitor b. So the charge on the plate is \(-\frac{q}{2}\). The (induced)charge on the other plate=\(+\frac{q}{2}\). If the question asks for the magnitude of charge on each plate of B, ans is \((2)\frac{q}{2}\).

But if the question asks for the net charge on capacitor B, ans is zero.

Krishna Jha - 4 years, 4 months ago

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Yep, that's what I thought too.

Rohan Rao - 4 years, 4 months ago

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