# What is the charge on the capacotor?

Q:Consider the situation shown in the figure. The capacitor A has a charge q on it whereas B is uncharged.The charge appearing on the capacitor B a long time after the switch is closed is:

Note by Rajath Krishna R
4 years, 9 months ago

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Ans. should be either $$(1)zero$$ or $$(2)\frac{q}{2}$$

The negative charge $$q$$ on the right capacitor plate of A is equally distributed between itself and the left plate of capacitor b. So the charge on the plate is $$-\frac{q}{2}$$. The (induced)charge on the other plate=$$+\frac{q}{2}$$. If the question asks for the magnitude of charge on each plate of B, ans is $$(2)\frac{q}{2}$$.

But if the question asks for the net charge on capacitor B, ans is zero.

- 4 years, 9 months ago

Yep, that's what I thought too.

- 4 years, 9 months ago