The basic algebra rule that both lhs and rhs are divided by 0....
see in algebra, we may divide things from lhs to rhs, but the basics are that, we dont actually take that number from lhs to rhs.... but divide both the lhs and rhs by the number, so dividing by zero will be impossible.....as you divide both lhs and rhs by zero, then it becomes 1.(0/0) = (0/0), where one of the (0/0) is considered as 1 by you in the third step and the other as undefined.......if u still dont understand, i will try to elaborate and send u a link later (which am not sending now cause am too lousy to search for it)...
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Anuj Modi
·
2 years, 8 months ago

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At the second to third step. You assume that the equation becomes, at LHS,

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TopNewestThe basic algebra rule that both lhs and rhs are divided by 0.... see in algebra, we may divide things from lhs to rhs, but the basics are that, we dont actually take that number from lhs to rhs.... but divide both the lhs and rhs by the number, so dividing by zero will be impossible.....as you divide both lhs and rhs by zero, then it becomes 1.(0/0) = (0/0), where one of the (0/0) is considered as 1 by you in the third step and the other as undefined.......if u still dont understand, i will try to elaborate and send u a link later (which am not sending now cause am too lousy to search for it)... – Anuj Modi · 2 years, 8 months ago

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At the second to third step. You assume that the equation becomes, at LHS,

\(1 * \frac{0}{0}=1\)

which aren't true. – Damiann Mangan · 3 years, 4 months ago

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