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My friend challenges me to solve the following:

\(\color{green}{\quad\text{What would be the solution to:}}\)

\(\color{green}{\quad\Large\frac{1}{3} + \frac{1}{7} + \frac{1}{8} + \frac{1}{15} + \frac{1}{24} + \frac{1}{26} + \frac{1}{31} + \frac{1}{35} + \cdots}\)

Note by Bloons Qoth
1 year, 2 months ago

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  Easy Math Editor

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How are the denominators progressing? I mean what is the pattern?

Yatin Khanna - 1 year, 2 months ago

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Not very sure but I couldn't help but notice this: 3=(2^2)-1,7=(2^3)-1,15=(2^4)-1,31=(2^5)-1..... 8=(3^2)-1,26=(3^3)-1...... 15=(4^2)-1(already included) 24=(5^2)-1........ 35=(6^2)-1........

Brilliant Member - 1 year, 2 months ago

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My friend simply send me this, and asks me to solve it. At the moment, I can't really tell what the pattern is. I guess it is part of the problem.

Bloons Qoth - 1 year, 2 months ago

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Cool! I will definitely try this one..

Yatin Khanna - 1 year, 2 months ago

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