If length of a conducting wire is increased by \(0.1\)%, the the resistance will increase by how much percentage?
2 years, 2 months ago
Resistance of a wire depends inversely on area of cross section and directly on length of wire.
But, since volume of wire remains constant, an increase in length causes a decrease in area. Dividing the new length by new area obtained, we get the new resistance.Subtract 1 from this and then multiply by 100.This will give you the %.The calculation is not long, but it involves big numbers like 1000 and 1001(even their squares!).Use difference of 2 squares rule(HINT).Calculate, and u will get the answer very close to 0.2(actually, 0.2001).
Sorry, couldn't show the calculation here!
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Thanks for your help.
You are welcome!
Answer should be 0.2%.
@Calvin Lin ,@Chung Kevin ,@Nihar Mahajan , @Mehul Arora ....plz help!!!
First, Thanks for mentioning me, Though I don't deserve that honour :)
Then, When a wire is stretched by x%, Then resistance will increase by 2x%. but this is applicable only x<10 (I don't know why, though)
Thus the answer should be 0.2%
Thanks...you really helped me!
Always welcome brother! :)
Well....i am a girl. ;)
Sorry, Sister* :P