Say the perimeter of a unit cube is 12, because that's the sum of all its edges, hence it's the cube's perimeter.

What would it be for a sphere of any proportion?

No vote yet

5 votes

×

Problem Loading...

Note Loading...

Set Loading...

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestWe don't call the sum of the edge lengths of a polyhedron its "perimeter." A perimeter is the boundary of a two-dimensional figure.

Because a sphere has no edges, it has no such sum as you have defined with the cube. Your question is analogous to asking for the number of vertices of a circle. There is none.

Log in to reply

I interpret it as the sum of edges of a solid by your example of a cube. But a sphere has no edges, so the 'perimeter' is 0. If you are talking about adding all those tiny circumferences of the sphere up, you end up integrating them into the surface area of the sphere, \(4\pi r^2\).

Log in to reply

Well you're just too smart for a 14 year old. I think that is kinda the answer.

Log in to reply

Correct.Log in to reply

probably undefined since there are no edges on a sphere

Log in to reply

i don't think it has a perimeter......as it is a 3D figure........

Log in to reply

bebzz.... see figure chaiye 3D ho yah 2D ....hum haar time perimeter find kaar sakte hai because vo humesha hi line segments se banni hoti hai .... and the figures with curves ,,hum unka circumfrence find kaar sakte hai ...."CIRCUMFRENCE" ......................remember hum circle ka circumfrence find karte thei......... same way sphere ka bhi circumfrence nikkal sakta hai.

Log in to reply

srry cant read hindi lol XD

Log in to reply

AND I would like to say one more thing.....next time dont...put ur silly...comments...in hindi.....

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

ohk.....toh aap meko sphere ka " CIRCUMFERENCE " find karke do.....plzzzzz........woh bhi curve hai na........? :/

[ i said

fine! if is it so...then find "CIRCUMFERENCE" of...sphere since its a curve tooo....]

as u quoted "and the figures with curves ,,hum unka circumfrence find kaar sakte hai ...."CIRCUMFRENCE" same way sphere ka bhi circumfrence nikkal sakta hai. "

aur jab ho jae toh btana....me yahi milungi....except for the condition ki tum use kisise pucho ya fir koi search engine khol kar uspe se copy...paste karo.....huh....

[ i said when u'll finish that....post it here i'll be here only.....and terms and conditions for u.....DONT ASK IT FROM SOMEONE AND DONT CHEAT IT FROM SOME SEARCH ENGINE.....OK...]

Log in to reply

We define perimeter for 2-dimensional figures only.

Log in to reply

There is no perimeter in 3 dimensional.Please clarify your question

Log in to reply

Tim Y. has already defined a "perimeter" of a 3D solid to be the sum of its edges. It is on our part, and not his, to understand what is implied.

Log in to reply

Perimeter doesn't apply to 3 dimensional figures. It is the boundary of a 2 dimensional figure.Since, 3 dimensional figures don't have any boundary , so, neither a sphere nor a cube has a perimeter.

Log in to reply

Well, going by your definition, lets say the sphere has infinite sides, then Perimeter = (infinity) x (whatever is the value of each side) p = ∞ But wait, the length of each side is zero as they are just points. ∴ p = ∞ x 0 = 1 (if you can consider that as true) Hence your answer is 1.

Log in to reply

Guyss.... first of all , cube is also a 3D figure and In the figures like that of a circle or a sphere ,we don't take perimeter ,there it's circumfrence . And in sphere we can have the circumfrence .. agree?

Log in to reply