I wanted to express

\(\large{\displaystyle \int_{0}^{1} \frac{dx}{\sqrt{1+x^{4}}}}\) in terms of beta function

I started with \(x=\sqrt{\tan t}\), then got the integral in form of \(sin2t\) and again substituted \(sin2t=z\) , after this i couldn't solve

## Comments

Sort by:

TopNewestI assume you got to this point: \( \displaystyle \frac 1{\sqrt2} \int_0^{\pi /4} (\sin(2t))^{-1/2} \, dt \),

Now let \(y = 2t \), you get \( \displaystyle \frac1{2\sqrt2} \int_0^{\pi /2} (\sin(y))^{-1/2} \, dy \).

Compare with equation 14 and equation 1 from this page.

And apply Euler Reflection Formula, you should get the answer of \( \frac1{8\sqrt\pi} \left [ \Gamma \left( \frac 14\right)^2 \right ] \). – Pi Han Goh · 1 year, 9 months ago

Log in to reply

– Tanishq Varshney · 1 year, 9 months ago

Thanx for the help \(\ddot \smile\)Log in to reply

@Azhaghu Roopesh M @Brian Charlesworth sir @Rajdeep Dhingra – Tanishq Varshney · 1 year, 9 months ago

Log in to reply

– Azhaghu Roopesh M · 1 year, 9 months ago

Sry couldn't make it in time . Btw are you participating in Proofathon ?Log in to reply

– Tanishq Varshney · 1 year, 9 months ago

Nope, i am just a beginner to all this , not good as all other members on brilliantLog in to reply

– Azhaghu Roopesh M · 1 year, 9 months ago

No prob , just give it a try .Btw I am not able to solve 4 questions as of now .Log in to reply