Attention

I, Rahil sehgal and Ankit Kumar made an whtsapp brillliant group. Interested persons can provide their whatsapp number. I will add you all

Note by Md Zuhair
1 year, 9 months ago

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1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

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@Md Zuhair

Ankit Kumar Jain - 1 year, 9 months ago

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+2348103182839...Please add me to the group.. I will be very happy

Ayanlaja Adebola - 1 year, 9 months ago

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@Md Zuhair @Rahil Sehgal @Ankit Kumar Jain - I also want to join. Please add me.

Aaron Jerry Ninan - 1 year, 9 months ago

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Pls comment your contact number below so that I can add u. :)

Rahil Sehgal - 1 year, 9 months ago

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@Rahil Sehgal what all will you discuss in the group

Aaron Jerry Ninan - 1 year, 9 months ago

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Please comment if you got it.

Aaron Jerry Ninan - 1 year, 9 months ago

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Thanks...

I have added you in the group

Rahil Sehgal - 1 year, 9 months ago

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Thanks.

Aaron Jerry Ninan - 1 year, 9 months ago

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@Md Zuhair @Rahil Sehgal - Can you please add me to the group too?

Thomas Jacob - 1 year, 8 months ago

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You can comment your contact number below. Thanks.

Rahil Sehgal - 1 year, 8 months ago

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Would you please add me too ,my number is 8547853228

Syed Shahabudeen - 1 year, 7 months ago

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What kind of group is it ? Formal one for physics and math problems ?

Nashita Rahman - 3 months, 3 weeks ago

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Kind of.....

Md Zuhair - 3 months, 3 weeks ago

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Ohh okay!

Nashita Rahman - 3 months, 3 weeks ago

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Quora misses you bro ;) How's your studies going? Also, tell me how are you motivating yourself everyday? And not to forget only one day left for this year to end LoL xD

Nashita Rahman - 2 weeks, 2 days ago

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@Nashita Rahman Well lets see... :)

Md Zuhair - 2 weeks ago

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@Md Zuhair Okay study harder bro!

Nashita Rahman - 2 weeks ago

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Happy New Year!

Nashita Rahman - 2 weeks, 1 day ago

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@Nashita Rahman Happy new year!!!!

Md Zuhair - 2 weeks ago

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Are you still adding students ? BTW I'm a JEE aspirant and I'm quite new to brilliant(Using it just for 1-1.5 months)

Richeek Das - 1 week ago

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+919903607651

Richeek Das - 1 week ago

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no bro... actually i deleted Whatsapp 6-7 month before :P

Md Zuhair - 6 days, 11 hours ago

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@Md Zuhair Me too , thats my mom'd :p Btw , we can be friends !

Richeek Das - 5 days, 23 hours ago

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Obviously. Friends with toppers like you would be a nice thing Id love to

Md Zuhair - 5 days, 21 hours ago

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What do you mean by "topper" ? -_- Do you even know me ?

Richeek Das - 5 days, 19 hours ago

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your credentials say all :)

Md Zuhair - 5 days, 18 hours ago

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@Md Zuhair That's nothing much I guess :p I see you are in South Point! I stay in Kolkata(30kms from it though) too ! I am in North Kolkata Fiitjee.

Richeek Das - 4 days, 19 hours ago

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@Richeek Das Arre... Then I know you. I have a friend named Rishav Dugar. He said the you are the smaller version of Arka Das. So I know you that you are a topper!!!

Md Zuhair - 4 days, 16 hours ago

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@Md Zuhair :( Unfortunately people think that . I am nowhere close to him .

Richeek Das - 4 days, 16 hours ago

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@Richeek Das But u defeat him in some exams.

Md Zuhair - 4 days, 15 hours ago

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@Md Zuhair Defeat"ed" in some .My Exam temperament is completely broken , nowadays :(

Richeek Das - 4 days, 14 hours ago

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@Richeek Das https://brilliant.org/problems/too-many-lenses/?ref_id=1559097

please help me with this!

Richeek Das - 4 days, 1 hour ago

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@Richeek Das I tried it this way. Taking the lens to be thin. I found the number of lens it will overcome until it reaches 3.925cm . Now taking the equivalent of all those lenes we ge the point where the ray would have passed if there were no further lens cutting the principal axis (focal pt) . Ebar....Using perpendicular/base.... =Tan theta(theta is angle b/w ray and principal axis). We can find out the height. If I am wrong somewhere.... Plz correct me. My answer is not matching.

Md Zuhair - 4 days ago

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The exact answer is \(y = hcos(\frac{x}{\sqrt(lf)})\)

Richeek Das - 3 days, 19 hours ago

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Oh so we need to find out the exact path of ray. I thought approximation would work

Md Zuhair - 3 days, 17 hours ago

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Ya

Richeek Das - 3 days, 16 hours ago

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@Richeek Das https://brilliant.org/problems/when-einstein-meets-huygens/

I have solved this , but I want to know if there is any better solution than what i have done ! Help me.

Richeek Das - 21 hours ago

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