I know that log function is defined only for positive reals but please help me understand where i go wrong in the following proof : TO PROVE : \[ \ln\big(i) = \frac{i\pi}{2} \] PROOF : \[ \ln(i) = \ln(e^{\frac{i\pi}{2}}) \] but we know that \[ \ln(e^x) = x \] and hence \[ \ln(i) = \ln(e^{\frac{i\pi}{2}}) = \frac{i\pi}{2} \] Hence proved . Is it correct ? Although , i am sure it is wrong but which step is precisely not allowed here?

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TopNewestit's not the same the exponentation or logharythmic functions with the complex numbers, that the exponentation or logharytmic functions with real numbers. Look at this : \(i = e^{ \frac {i \pi}{2}} =e^{ \frac {5i \pi}{2}}\)... – Guillermo Templado · 7 months, 2 weeks ago

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– Starwar Clone · 7 months, 1 week ago

thanks for the help :)Log in to reply

– Guillermo Templado · 7 months, 1 week ago

If you need something about me, you can ask to me, and if I can help you, I'll help you.Log in to reply

– Starwar Clone · 7 months, 1 week ago

thank you ...Log in to reply

– Guillermo Templado · 7 months, 1 week ago

thank you for you,of courseLog in to reply

– Starwar Clone · 7 months, 1 week ago

this discussion has turned out to be fun......all are becoming friends :)Log in to reply

– Guillermo Templado · 7 months, 1 week ago

thank you again friend... I like that we are all friendsLog in to reply

Hello my friend again – Guillermo Templado · 7 months, 2 weeks ago

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What makes you think that \( \ln i \neq \frac{ i \pi } { 2} \)?

Also, be very careful with complex exponentiation and logarithms. – Calvin Lin Staff · 7 months, 2 weeks ago

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The sequence of steps that you took essentially work, but you have to be clear if you are working with "equality of multi-valued functions" or "evaluate at primitive branch".

To be clear, the multi-valued function \( \ln i \) is indeed equal to \( \frac{ i \pi }{2} + 2k \pi i \). – Calvin Lin Staff · 7 months, 1 week ago

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– Guillermo Templado · 7 months, 1 week ago

Calvin, please, I want to be your friend, but you don't make me easy it... \(\frac{i \pi}{2} + 2k\pi \neq i\cdot(\frac{\pi}{2} + 2k \pi)\)Log in to reply

– Calvin Lin Staff · 7 months, 1 week ago

Ah yes, fixed the typo. thanks.Log in to reply

– Guillermo Templado · 7 months, 1 week ago

Don't worry, can we be friends?Log in to reply

– Calvin Lin Staff · 7 months, 1 week ago

Of course!Log in to reply

– Guillermo Templado · 7 months, 1 week ago

Thank you very much.Log in to reply

a) Where can I start?

b) I can't do everything, I'm not God/Godness or...

c) For example, suppose I want to write a wiki on numerical analysis, before doing this, would I have to define what a vectorial space is, would I have to give a topology or abstract algebra course first, would I have to establish some prior knowledge of mathematical analysis?...

d) In short, what would I have to do? – Guillermo Templado · 7 months, 1 week ago

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If you're working on a new wiki and need help with developing the outline, let me know.

Don't worry about it. Focus on what you're good at / what you're interested in.

Do not worry about ensuring that foundational material exists when developing out a page. We can fill that in subsequently. and use "red links" to indicate that wiki pages are undeveloped. E.g. In the Gram Schmidt wiki, we would assume knowledge of vector space, and link out to it.

Where do you want to start?

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P.S.- Imagine that I am nobody, neither a mathematician nor a physicist .. – Guillermo Templado · 7 months, 1 week ago

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– Guillermo Templado · 7 months, 1 week ago

Look, we can make one thing, I like so much topology, and here I don't see Topology. What about if I start talking about Topology, with more or less a notion of a "set", I'll "definite it", I don't want Russell's paradox again... do you remember what happened...? and later I continue talking about Topology, and when I need help, I can email you or stop... Remember, we are free if we respect ourselves... what do you think about this?... I have other question: where is Mateo Matija...? I can't get see him... It's important for me...Log in to reply

@Guillermo Templado sir , this doubt arose from your solution to imaginary^imaginary . Can you please help me? – Starwar Clone · 7 months, 2 weeks ago

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– Guillermo Templado · 7 months, 2 weeks ago

Yes, I'm going on there...Log in to reply