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# Where's the relationship between the two points?

Let $$ABCD$$ be a parallelogram. Let the bisector of angle $$BAD$$ intersect the line $$CD$$ at $$F$$ and the line $$BC$$ at $$G$$. Prove that the circumcentre of triangle $$CFG$$ lies on the circumcircle of triangle $$BCD$$

Note by Sharky Kesa
1 year, 11 months ago

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