If \(xyz=-1\), then the value of \( \sqrt [ 4 ]{ \left( xyz \right)^4 } \) is

**Option 1** : 1

Why?

Because

\[\Large{ \sqrt [ 4 ]{ \left( xyz \right)^4} =\sqrt [ 4 ]{ \left( -1 \right) ^{ 4 } } =\sqrt [ 4 ]{ 1 } =1}\]

**Option 2** : -1

Why?

Because

\[\Large{\sqrt [ 4 ]{ \left( xyz \right) ^{ 4 } }=xyz=-1}\]

**Option 3** : \(i\)

Why?

Because

\[\Large{\sqrt [ 4 ]{ \left( xyz \right) ^{ 4 } } =\quad \sqrt [ 4 ]{ \left( xyz \right) ^{ 3 } } \times \sqrt [ 4 ]{ xyz } =\sqrt { i } \times \sqrt { i } =i}\]

Explanation required

## Comments

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TopNewestI think this one example may help you.

Ex. \((\sqrt{-1})^2 \neq \sqrt{(-1)^2}\)

LHS: \((\sqrt{-1})^2 = -1 \)RHS: \(\sqrt{(-1)^2} = |-1| = 1 \)I think all the options are correct. Given equation has 4 roots.i.e \(1 , -1 , \iota , -\iota\) – Akhil Bansal · 1 year, 3 months ago

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let x = xyz^4 so x will have roots ie i,-1,1,one more – Genius Literally · 1 year, 3 months ago

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Option 1. First condition: xyz= -1 – Ma Pm · 1 year, 3 months ago

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Option 1, because the property that (a)^(mn)=a^m*a^n is only preserved for real numbers. – Aditya Agarwal · 1 year, 3 months ago

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Option \(0!\) – Hjalmar Orellana Soto · 1 year, 3 months ago

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option 1 guaranteed .option 2-no because the root sign stands for only positive values and option 3 -no because u cant do it for unreal numbers – Kaustubh Miglani · 1 year, 3 months ago

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Option 1 – Deepak Kumar · 1 year, 3 months ago

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– Lakshya Sinha · 1 year, 3 months ago

Explanation requiredLog in to reply

– Deepak Kumar · 1 year, 3 months ago

(x^2n)^(1/2n)=|x|Log in to reply

– Lakshya Sinha · 1 year, 3 months ago

NiceLog in to reply

– Ravi Dwivedi · 1 year, 3 months ago

Ya correct explanation.....its option 1Log in to reply