A number \(x\), to the power \(a\), and another arbitrary constant \(b\), can be considered as follows: \( \dfrac{x^{a+b}}{x^b} \). Simplifying this fraction, through rules of exponents, we know that it is the same as \(x^{a+b - (b)} = x^a\). So let's look at 0. \(0^1 = \dfrac{0^{1+2}}{0^2} \). Since we know both \(0^1 \) and \(0^2\) are 0, does it not follow that \(\dfrac00 = 0 \)?

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TopNewestThe rules of exponents are for non zero \(x\).

As such, division by zero is undefined. – Deeparaj Bhat · 10 months, 1 week ago

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– M K · 10 months, 1 week ago

Ah I see. Thanks for clarifying!Log in to reply

– Deeparaj Bhat · 10 months, 1 week ago

You're welcome. :)Log in to reply

0/0 can't be 0 cos it is undefined or sometimes be intermediate. You can confirm using your calculator. That why calculator can't solve such problem. – Ayanlaja Adebola · 10 months, 1 week ago

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