Will you Help me?

I am unable to derive the equation for the minimum velocity required to make a round in a loop. Can you help me ?

At first, I have to derive the expression for minimum velocity in a circular loop like this

Will the expression be same in this case as well?

Note by Kaushik Chandra
12 months ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

Use conservation of energy to determine the kinetic energy (and speed) at any point on the circle, assuming the object starts on the bottom. The kinetic energy gives the centripetal force, which is a combination of the gravity component in the radial direction, plus a reaction force from the surface. This reaction force can't be negative (the surface can push but can't pull). Therefore, that is the requirement. Determine the minimum initial speed such that the reaction force is never negative, when going from the bottom to the top.

Steven Chase - 11 months, 3 weeks ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...