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You lift a 450 N bag of rice 1.2 metres and carry it a distance of 10 metres to the kitchen. How much work is done?

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W=F.S Cos(theta)

We have to know the 'THETA' Which is point of application of force

In this case, Only Force and displacement , there is no use of length of sack

Simply if we take W=F.S and Cos180°= (-1) So,W=450x 10x (-1) =(-4500)

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Hiii mi Narayan...how is it

Zero

450*1.2

Work done will be zero as the angle between force (in verticle direction against gravity) and displacement (if kitchen is in same horizontal plane) is 90.

Where is the kitchen located relative to where the rice was?

John weighing 40 kg claimbs up a staircase of 20 steps,each of 16 cm height, in 20 seconds. Find the power generated by him.

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TopNewestW=F.S Cos(theta)

We have to know the 'THETA' Which is point of application of force

In this case, Only Force and displacement , there is no use of length of sack

Simply if we take W=F.S and Cos180°= (-1) So,W=450x 10x (-1) =(-4500)

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Hiii mi Narayan...how is it

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Zero

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450*1.2

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Work done will be zero as the angle between force (in verticle direction against gravity) and displacement (if kitchen is in same horizontal plane) is 90.

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Where is the kitchen located relative to where the rice was?

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John weighing 40 kg claimbs up a staircase of 20 steps,each of 16 cm height, in 20 seconds. Find the power generated by him.

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