Geometry
# 2D Coordinate Geometry

What is the area enclosed by $(y-x)^{2}=4$ and $(y+x)^{2}=4?$

Triangle $ABC$ has coodinates $A= (-4, 0)$, $B= (4 , 0)$, and $C= (0 , 3)$.

Let $P$ be the point in the first quadrant such that $\triangle ABP$ has half the area of $\triangle ABC$ but both triangles have the same perimeter.

What is the length of $CP?$ If your solution is in a form of $\sqrt{d}$, submit $d$ as the answer.

$ABC$ is an equilateral triangle such that vertices $B,C$ lie on two parallel lines at a distance of 6 units. If $A$ lies between the parallel lines at a distance 4 units from one of them, then the length of the side of the triangle is of the form

$\large{A\sqrt{\frac{B}{C}}}$, where $A,B,C$ are co prime natural numbers.

Find $A+B+C$.

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