Electricity and Magnetism
# Magnetic Flux, Induction, and Ampere's Circuital Law

The magnetic constant is \( \mu_0 = 4 \pi \times 10^{-7} \text{ H/m}. \)

Assume \( OQ = OT = a = 2 \text{ cm}.\)

The magnetic constant is \( \mu_0 = 4 \pi \times 10^{-7} \text{ H/m}. \)

The magnetic constant is \( mu_0 = 4 \pi \times 10^{-7} \text{ H/m}. \)

The worker can twist the wire in two ways shown in the picture above. If the radius of the loop is \(r\), and the magnetic field strength at a distance \(r\) from a straight wire was \(H_0 = 10~\mbox{A/m}\), what is the difference between the magnetic field strength in the middle of the loop in the case a) and b) **in A/m**?

**Details and assumptions**

- Your answer should be the absolute value of the difference between the fields.

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