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If two numbers have arithmetic mean 2700 and harmonic mean 75, then find their geometric mean.

**Note**:

The arithmetic mean of two numbers \(a\) and \(b\) is \(\frac{a+b}2\).

The harmonic mean of two numbers \(a\) and \(b\) is \( \frac2{1/a + 1/b} \).

\[1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + \ldots + 301 + 302 = ?\]

**Clarification**: The sum keeps alternating between two distinct positive numbers and two distinct negative numbers.

Real numbers \(a_1,a_2,\ldots,a_{99}\) form an arithmetic progression.

Suppose that \[ a_2+a_5+a_8+\cdots+a_{98}=205.\]

Find the value of \( \displaystyle \sum_{k=1}^{99} a_k\).

\(a_1,a_2,a_3,\ldots, a_{98} \) are terms in an arithmetic progression with common difference 1 such that their sum is 137.

What is the sum of the even terms of this progression? That is, what is the value of \( a_2+a_4+a_6+\cdots+a_{98} \)?

\[\large 54+51+48+45+ \cdots\]

You are given the sum of an arithmetic progression of a finite number of terms as shown above.

What is the minimum number of terms used to make a total value of 513?

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