Classical Mechanics
# Moment of Inertia

Three particles of respective masses \(m_1=12.0\text{ kg},\) \(m_2=25.0\text{ kg}\) and \(m_3=38.0\text{ kg}\) form an equilateral triangle of side length \(a=140\text{ cm}.\) If we locate \(m_1\) at the origin on the \(xy\)-plane, and put \(m_2\) to the right of \(m_1\) on the \(x\)-axis, as shown in the above figure, what are the approximate coordinates of the center of mass of this system?

The value of \(\sqrt{3}\) is \(1.732.\)

Three particles of respective masses \(m_1=13.0\text{ kg},\) \(m_2=29.0\text{ kg}\) and \(m_3=37.0\text{ kg}\) form an equilateral triangle of side length \(a=140\text{ cm}.\) If we locate \(m_1\) at the origin on the \(xy\)-plane, and put \(m_2\) to the right of \(m_1\) on the \(x\)-axis, as shown in the above figure, what are the approximate coordinates of the center of mass of this system?

The value of \(\sqrt{3}\) is \(1.732.\)

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