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Excel in math and science.

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Solving Equations

Isolating a Variable

Solve the following for \(Y\) in terms of \(X:\) \[ X = 6Y .\]

\[ Y={X}+{6} \] \[ Y={6}X \] \[ Y=\frac{X}{6} \] \[ Y=\frac{6}{X} \]

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by Brilliant Staff

Given the equation \( X = 2 Y + 7, \) solve for \(Y\) in terms of \(X\).

\[ Y = \frac{ X - 2} { 7} \] \[ Y = \frac{ X - 7} { 2} \] \[ Y = \frac{ X + 2} { 7} \] \[ Y = \frac{ X + 7} { 2} \]

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by Brilliant Staff

Solve the following for \(Y\) in terms of \(X:\) \[ \frac{Y+2}{X+7} = 1.\]

\[ Y=X+{7} \] \[ Y=\frac{X}{5} \] \[ Y=X+{5} \] \[ Y=\frac{X}{7} \]

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by Brilliant Staff

Joshua has 5 times as many toys as Kevin.

Joshua has 8 more toys than Larry.

If Larry has \(L\) toys and Kevin has \(K\) toys, which of the following expresses \(K\) in terms of \(L\)?

\[K = \frac{L+8} { 5} \] \[K = \frac{L+5} { 8} \] \[K = 8 L+5 \] \[K = 5 L+8 \]

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by Brilliant Staff

Given the equation \( X = 3 Y + 6, \) solve for \(Y\) in terms of \(X\).

\[ Y = \frac{ X - 6} { 3} \] \[ Y = \frac{ X + 3} { 6} \] \[ Y = \frac{ X + 6} { 3} \] \[ Y = \frac{ X - 3} { 6} \]

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by Brilliant Staff

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