Algebra
# Classical Inequalities

For positive real numbers $a,b,c,d,$ find the minimum value of the following expression:

$\displaystyle (a+b+c+d)\Bigl( \dfrac{25}{a} + \dfrac{36}{b} +\dfrac{81}{c} +\dfrac{144}{d} \Bigr).$

Consider all positive reals $a$ and $b$ such that

$ab (a+b) = 2000.$

What is the minimum value of

$\frac{1}{a} + \frac{1}{b} + \frac{1}{a+b} ?$

$a, b$ and $c$ are positive real numbers satisfying $a + b + c = 100$. The maximum value of

$a + \sqrt{ab} + \sqrt[3]{abc}$

can be expressed as $\dfrac{m}{n}$, where $m$ and $n$ are coprime positive integers. What is the value of $m+n$?