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Electric Flux
Electric flux connects the geometry of conductors to the fields they generate. Learn this powerful tool and shortcut your way to the electric field of symmetrical arrangements like wires and sheets.
If the total charge on the surface of a conducting sphere is \(2.3 \,\mu\text{C}\) and the diameter of the sphere is \(1.1\text{ m},\) what is the magnitude of the electric field just outside the surface of the sphere, due to the surface charge?
The value of the permittivity constant is \(\varepsilon_0=8.85 \times 10^{-12} \text{ C}^2\text{/N}\cdot\text{m}^2.\)
The value of the permittivity constant is \(\varepsilon_0=8.85 \times 10^{-12} \text{ C}^2\text{/N}\cdot\text{m}^2.\)
If an isolated conductor has net charge \(+15.0 \times 10^{-6}\text{ C}\) and a cavity with a point charge \(q=+4.0 \times 10^{-6}\text{ C},\) what are the charge of the cavity wall \(q_w\) and the charge on the outer surface \(q_s?\)
Consider a uniformly charged conducting sphere. If the radius of the sphere is \(0.50\text{ m}\) and the surface charge density is \(8.40 \,\mu\text{C/m}^2,\) what is the approximate total electric flux leaving the surface of the sphere?
The value of the permittivity constant is \(\varepsilon_0=8.85 \times 10^{-12} \text{ C}^2\text{/N}\cdot\text{m}^2.\)
If the magnitude of electric field just above the surface of a charged conducting cylinder is \(2.8 \times 10^5 \text{ N/C},\) what is the surface charge density of the cylinder?
The value of the permittivity constant is \(\varepsilon_0=8.85 \times 10^{-12} \text{ C}^2\text{/N}\cdot\text{m}^2.\)