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Electric Fields
Electric fields describe the interaction of stationary charged matter. They underlie the working of diverse technology from atom smashers to the poor cell reception you're getting right now.
Two large, parallel conducting plates are \( d = 10 \text{ cm} \) apart and have charges of equal magnitude and opposite sign on their facing surfaces. An electric field of strength \( E = 4.00 \times 10^4 \text{ N/C}\) acts on an electron placed anywhere between the two plates. (Neglect fringing.) What is the potential difference between the plates?
A charge of \( 6.0 \text{ nC}, \) is initially at a point that is \( r_1 = 3.0 \text{ m}, \) away from a charge of \( 1.0 \text{ nC} \) moves further away to a point where the distance is \(r_2= 7.0 \text{ m}. \) What is the approximate potential difference between the two points.
Assume that electric constant is \( \epsilon_0 = 8.9 \times 10^{-12} \text{ F/m}. \)
A 9V battery has an electric potential difference of \(9~\mbox{V}\) between the positive and negative terminals. How much kinetic energy in J would an electron gain if it moved from the negative terminal to the positive one?
Details and assumptions
- The charge on the electron is \(-1.6 \times 10^{-19}~\mbox{C}\).
- You may assume energy is conserved (so no drag or energy loss due to resistance for the electron).
Assume that electric constant is \( \epsilon_0 = 8.9 \times 10^{-12} \text{ F/m} \) and \( \sqrt{2} \) is \( 1.4. \)