Electricity and Magnetism
# Electric Flux

The value of the permittivity constant is \(\varepsilon_0=8.85 \times 10^{-12} \text{ C}^2\text{/N}\cdot\text{m}^2.\)

The electric field in a certain device is vertically downward. At a height of \(27\text{ m}\) from the bottom of the device the magnitude of electric field is \(50.0 \text{ N/C},\) and at a height of \(18\text{ m}\) from the bottom the magnitude of electric field is \(80.0\text{ N/C}.\) If the bottom face of a cube with side length \(9\text{ m}\) is at a height of \(18\text{ m}\) from the bottom of the device, what is the approximate net amount of charge contained in the cube?

The value of the permittivity constant is \(\varepsilon_0=8.85 \times 10^{-12} \text{ C}^2\text{/N}\cdot\text{m}^2.\)

The value of the permittivity constant is \(\varepsilon_0=8.85 \times 10^{-12} \text{ C}^2\text{/N}\cdot\text{m}^2.\)

The charge of a proton is \(q=+1.6 \times 10^{-19}\text{ C}\) and the value of the permittivity constant is \(\varepsilon_0=8.85 \times 10^{-12} \text{ C}^2\text{/N}\cdot\text{m}^2.\)

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