Calculus
# Limits of Functions

$\lim_{x\to\infty} \dfrac{\sin x}x = \, ?$

$\Large \lim_{x\rightarrow 0} \frac{|2x-1|-|2x+1|}{x}= \ ?$

$f(x) = \large{\begin{cases} (x^2 - 4)/(x-2), & \text{ if } x < 2 \\ 2, & \text{ if } x = 2 \\ x^3-3x^2 + 2x + 4 , & \text{ if } x > 2 \\ \end{cases} }$

Compute $\displaystyle \lim_{x \to 2} f(x)$.

$\large \lim_{x \to 0} \, \left \lfloor \dfrac{(\sin x) (\tan x)}{x^2} \right \rfloor = \ ?$