An astronomical unit is the average distance from the earth to the sun. (The earth's orbit is slightly elliptical, so it isn't always the same distance.) The abbreviation is AU.
Saturn is approximately 9.6 AU from the Sun. On the linear scale below, where will Saturn be?
Let's add some more objects to our scale, including the edge of the universe.
| Object | Distance from Sun |
| Earth | 1 AU |
| Jupiter | 5.2 AU |
| Saturn | 9.6 AU |
| Heliopause (edge of the solar system) | 120 AU |
| Nearest black hole | 200,000,000 AU |
| Edge of observable universe | 900,000,000,000,000 AU |
Which depiction accurately places all the objects on a linear scale?
Given the entire universe essentially collapses on the same point when trying to plot it on a linear scale, a more useful chart is a logarithmic scale.
With a linear scale, moving forward a step adds to the distance a set amount.
With a logarithmic scale, moving forward a step multiplies the distance by a set amount. For the diagram below, each step forward represents a 10-fold multiplication of the distance.
The chart above has 7 steps visible. If it continues that pattern as shown, how many steps will the chart need to accurately include 900,000,000,000,000 (900 trillion, or AU?
If we take the logarithm at a particular point on the chart (past 1 AU), we get how many steps it is along the scale. For example, the logarithm (base 10) of is 4, and that number is 4 steps along the scale.
If you start at some point at distance from the sun and travel 2 steps to the right, followed by 3 steps, how far are you now from the sun?
Here's a hint why it's useful to think in terms of logarithmic scales.
What expression is equivalent to
Just like we can think of regular arithmetic as shifting around a number line, we can think of logarithm arithmetic as being done on a logarithmic scale. We can derive all the rules for logarithms starting from this idea.
Pre-Calculus can be done naturally and intuitively: get started and find out how!