Numerical Approximation of Integrals: Level 4 Challenges Practice Problems Online

Using the Left-hand Rectangular Approximation Method and 11 rectangles, approximate

$\large \int_{0}^{1}x^3dx .$

Give your answer to 4 decimal places.

$\begin{aligned} S_{1}&=&\sqrt[22]{1887}+\sqrt[22]{1888}+\cdots+\sqrt[22]{2013}+\sqrt[22]{2014} \\ \\ \ S_{2}&=&\sqrt[22]{1888}+\sqrt[22]{1889}+\cdots+\sqrt[22]{2014}+\sqrt[22]{2015} \\ \\ I&=&\int_{1887}^{2015}\!\sqrt[22]{x}\,\mathrm{d}x \end{aligned}$

What can you say about the relative values of $S_{1}$ , $S_{2}$ , and $I$ ?

S_{1}<S_{2}<I

S_{2}<S_{1}<I

S_{2}<I<S_{1}

S_{1}<I<S_{2}

I<S_{1}<S_{2}

I<S_{2}<S_{1}

$\large \begin{cases} {f(2013) = 3} \\ {f(2015) = 1} \\ {f(2017)=5} \\ {f(2019)=2015} \\ \end{cases}$

Given that a cubic polynomial $f(x)$ that satisfy the system of equations above, find the value of $\displaystyle \int_{2013}^{2017} f(x) \, dx$ .

For all cubic polynomials $f(x)$ , what positive value of $k$ makes the following statement true?

$\int_{-1}^{1}f(x)dx = f(-k) + f(k)$

Bonus question: What is this method of approximation known as?

$\bigg \lfloor \;10 \times \displaystyle \int_2^e \! \frac {1}{\ln(x)} \, \mathrm{d}x\;\bigg \rfloor = \ ?$

Details and Assumptions:

You may use the following approximations: $e \approx 2.718$ , and $\ln(2) \approx 0.693$ , and use the following graph of $f(x)= \frac {1}{\ln(x)}$ .

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Numerical Approximation of Integrals: Level 4 Challenges

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