Polar Equations - Surface Area Practice Problems Online

Find the area of the surface formed by revolving the curve $r = 5 \sin\theta$ from $\theta = 0$ to $\theta = \frac{\pi}{2}$ about the $x$ -axis.

Find the surface area generated when the curve $r = e^{\theta}$ from $\theta = 0$ to $\theta = \frac{\pi}{2}$ is revolved about the $y$ -axis.

\displaystyle{ \frac{\pi}{2}e^{\pi}}

\displaystyle{ \frac{\sqrt{3}\pi}{2} + \pi e^{\pi}}

\displaystyle{ \pi + 2 \pi e^{\pi}}

\displaystyle{ \frac{2 \sqrt{2} \pi}{5} e^{\pi} - \frac{4\sqrt{2}\pi}{5}}

Find the area of the surface formed by revolving the curve $r = 5 \sin\theta$ from $\theta = 0$ to $\theta = \frac{\pi}{2}$ about the $y$ -axis.

Find the area of the surface formed by revolving the curve $r = 3 \cos(\theta)$ from $\theta = 0$ to $\theta = \frac{\pi}{2}$ about the $x$ -axis.

Find the area of the surface formed by revolving the curve $r = 5 \cos{\theta}$ from $\theta = 0$ to $\theta = \frac{\pi}{2}$ about the $y$ -axis.

Polar Equations Calculus